Molarity Defination Uses Calculation
Molarity Definition
1Mole of solute dissolve in 1lit solution at given temperature that’s call Molarity (M).
There are two information are needed for calculating Molar Concentration
- The mole of solute present in the solution.
- The volume of solution.
Molarity Formula
\[M=\frac{Number\;Of\;Moles\;Of\;Solute}{Volume\;of\;solution\;in\;liter}\]
\[M=\frac{Weight\;Of\;Subs\tan ce/Molecular\;Weight}{Solution\;Qty/1000}\;\;\]
\[M=\frac{Weight\;Of\;Subs\tan ce\times1000}{Solution\;Qty\times\;M.W}\;\;\]
Expand Your Knowledge on [Normality]
Molarity Uses
The Molar Concentration of a solution can be used in the following ways :
- To find the unknown number of moles in a given volume of soliton.
- To find the volume of a solution under a given number of moles.
- To find the molality of a substance.
- To identify the concentration or dilution of a solution.
Molar Concentration Formula With Example
01) How much NAOH Required to make 2.0M NAOH 500ml solution ?
Weight of substance = ?
Solution Qty = 500 ml
M = 2
Molecular weight = 40 gram/mole
\[M=\frac{Weight\;Of\;Subs\tan ce\times1000}{Solution\;Qty\times\;M.W}\;\;\]
\[2=\frac{Weight\;Of\;Subs\tan ce\times1000}{500\times\;40}\;\;\]
\[Weight\;Of\;Subs\tan ce=\frac{2\times500\times40}{1000}\;\;\]
Weight of Substance = 40 Gram
02) 171 Gram dissolve in 2 lit water find the molar concentration of solution ?
Molecular Weight of sugar = 342 Gram/Mole
Solution Qty = 2 Liter = 2000 ml
Weight of Substance = 171 gram
\[M=\frac{Weight\;Of\;Subs\tan ce\times1000}{Solution\;Qty\times\;M.W}\;\;\]
\[M=\frac{171\times1000}{2000\times342}\;\;\]
M = 0.25
Expand Your Knowledge on [Molality]
03) A KOH solution with a volume of 400 ml contains 2 mole KOH. What is a Molarity of solution ?
Volume = 400ml = 0.4 liter
Mole of KOH = 2
\[M=\frac{Number\;Of\;Moles\;Of\;Solute}{Volume\;of\;solution\;in\;liter}\]
\[M=\frac2{0.4}\;\;\]
M = 5
04) A glucose solution with a volume 1.5 L contain 85 gram glucose (C6 H12 O6) ?
Weight of substance = 85 gram
Solution Qty = 1500 ml
M = ?
Molecular weight = 180 gram/mole
\[M=\frac{Weight\;Of\;Subs\tan ce\times1000}{Solution\;Qty\times\;M.W}\;\;\]
\[M=\frac{85\times1000}{1500\times180}\;\;\]
M = 0.31
